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Beam Load Support Formulas
  All Beam Load tables are for simple beams supported at the ends . These can be used in the majority of the cases . There are times when it is necessary to know what happens with other loading and support conditions . Some common arrangements are shown below . Simply multiply the values from the Beam Load tables by factors given below .
  Load and Support Condition
  Load Factor
  Deflection Factor
   Simple Beam
Uniform Load
   Span
       1 .00
   1 .00
  Simple Beam
Concentrated Load at Center
         0 .50
   0 .80
  Simple Beam
Two Equal Concentrated Loads at 1/4 Points
        1 .00
  1 .10
  Beam Fixed at Both Ends
Uniform Load
     1 .50
   0 .30
  Beam Fixed at Both Ends
Concentrated Load at Center
       1 .00
  0 .40
  Cantilever Beam
Uniform Load
     0 .25
   2 .40
  Cantilever Beam
Concentrated Load at End
        0 .12
   3 .20
  Continuous Beam
Two Equal Spans - Uniform Load on One Span
           Span Span
     1 .30
  0 .92
  Continuous Beam
Two Equal Spans - Uniform Load on Both Spans
     1 .00
   0 .42
  Continuous Beam
Two Equal Spans - Concentrated Load at Center of One Span
     0 .62
   0 .71
  Continuous Beam
Two Equal Spans - Concentrated Load at Center of Both Spans
           0 .67
   0 .48
         EXAMPLE I 60" 60" PROBLEM:
Calculate the load and deflection of an W200 beam continuous over one support and loaded uniformly on one span .
SOLUTION:
A . From load table for W200 the load for a 60" span is 700 lbs . and deflection is 0 .35" .
B . Multiply by factors from Table above Load = 700 lb . x 1 .30 = 910 lbs . Deflection = 0 .35 x 0 .92 = 0 .322" .
EXAMPLE II
PROBLEM:
24"
        – 4 –
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Determine load and deflection of an W150 cantilever beam with a concentrated load on the end .
SOLUTION:
A . From load table for W150 the load for a 24" span is 5,360 lbs . and deflection is 0 .09" .
B . Multiply by factors from Table above . Load = 5,360 lbs . x 0 .12 = 643 .2 lbs . Deflection - 0 .09 x 3 .20 = 0 .288"
 

































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